3160620 – Instrumentation and Sensors Study Materials, GTU Degree Civil Engineering Sem 6
3160620 – Instrumentation and Sensors Study Materials, GTU Degree Civil Engineering Sem 6 Also Visit GTU Degree Civil Engineering Sem 6 Study […]
Category: Civil Engineering Study Materials
Traffic Engineering and Management Study Materials, GTU Degree Civil Engineering Sem 6
3160615 – Traffic Engineering and Management Study Materials, GTU Degree Civil Engineering Sem 6 Also Visit GTU Degree Civil Engineering Sem 6 […]
Urban Transportation Planning Study Materials, GTU Degree Civil Sem 6
3160608 – Urban Transportation Planning Study Materials Also Visit GTU Degree Civil Engineering Sem 6 Study Materials Also Visit GTU Degree Civil […]
Drought And Causes of Drought
Drought Causes of drought 1. Amount of water vapour in the atmosphere Generally, rainfall is related to the amount of water vapour […]
Various Causes of Flood
Various causes of flood 1. Heavy rainfall Whenever there is heavy rain and the drainage system is not proper, it may result […]
Various Causes of Reservoir Sedimentation And Its Control
Various causes for the reservoir sedimentation 1. Nature of soil in the catchment area If the soil is sandy, loose and easily […]
Storage Zones of Reservoir
Storage zones of reservoir On the basis of the surface or pool level 1. Minimum Pool Level It is the lowest level […]
A peak of flood hydrograph due to 6 hr storm is 470 m3/s. The average depth of rainfall is 8 cms. Assume an infiltration loss of 0.25 cm/hour and a constant base flow of 15 m3/sec. Estimate the peak discharge of 6-hour unit for this catchment.
Duration of rainfall excess = 6 hr Infiltration loss = 0.25 cm/hr ∴ Total loss for 6 hr = 0.25 ∗ 6 […]
During the recuperation test of a 4.0 m open well a recuperation of the depression head from 2.5 m to 1.25 m was found to take place in 90 minutes. Determine specific capacity per unit well area. Also determine yield of well for safe drawdown of 2.5 m.
Given Data, Time of recuperator (Tr) = 90 min. = 90/60 hr = 1.5 hr Initial depression head (H1) = 2.5 m […]
Design an open well in fine sand to give a discharge of 0.03 cumec when worked under a depression head of 2.5 m.
Data Given, H = 2.5 m Q = 0.03 cumec (m3/s) Q = 0.03 ∗ 3600 m3/hour Q = 108 m3/hour For […]
