Design an open well in fine sand to give a discharge of 0.03 cumec when worked under a depression head of 2.5 m.

By Er. Mr. M. V.

Data Given,

H = 2.5 m

Q = 0.03 cumec (m3/s)

Q = 0.03 ∗ 3600 m3/hour

Q = 108 m3/hour

For open wells,

Q = (k/A)∙A∙H

108 = 0.50 * A * 2.5 [∵ For fine sand, (k/A) = 0.50 m3/hr]

∴ A = 86.4 m2

We know that,

A = ∏/4 * d2

86.4 = ∏/4 * d2

∴ d = 10.49 m

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